1. The problem asks to find the equation in slope-intercept form $y=mx+b$ that matches the given table of values: | x | y | |---|----| | 1 | -7 | | 2 | -10| | 3 | -13| | 4 | -16| 2. First, calculate the slope $m$ using any two points, for example $(1,-7)$ and $(2,-10)$: $$m=\frac{y_2 - y_1}{x_2 - x_1} = \frac{-10 - (-7)}{2 - 1} = \frac{-10 + 7}{1} = \frac{-3}{1} = -3$$ 3. Now use the slope $m=-3$ and one point, say $(1,-7)$, to find the y-intercept $b$ by substituting into $y=mx+b$: $$-7 = -3 \times 1 + b$$ $$-7 = -3 + b$$ Add 3 to both sides: $$-7 + 3 = b$$ $$b = -4$$ 4. Therefore, the equation is: $$y = -3x - 4$$ 5. Checking the options, this matches option c. Final answer: $y = -3x - 4$