1. **State the problem:** Convert the equation $2x + 4y = 8$ into slope-intercept form, which is $y = mx + b$ where $m$ is the slope and $b$ is the y-intercept. 2. **Start with the given equation:** $$2x + 4y = 8$$ 3. **Isolate the $y$ term:** Subtract $2x$ from both sides: $$\cancel{2x} + 4y - \cancel{2x} = 8 - 2x$$ $$4y = -2x + 8$$ 4. **Solve for $y$ by dividing both sides by 4:** $$y = \frac{-2x + 8}{4}$$ 5. **Simplify the fraction:** $$y = \frac{-2x}{4} + \frac{8}{4}$$ $$y = -\frac{1}{2}x + 2$$ 6. **Interpret the result:** The slope-intercept form is $y = -\frac{1}{2}x + 2$, where the slope $m = -\frac{1}{2}$ and the y-intercept $b = 2$. This means the line crosses the y-axis at 2 and goes down by 1 unit for every 2 units it moves to the right.