1. **State the problem:** Write the slope-intercept form $y=mx+b$ for the equations: - $3y + 12 = -12x$ - $x - 4y + 8 = 0$ 2. **Recall the slope-intercept form:** $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Solve equation 15: $3y + 12 = -12x$** - Subtract 12 from both sides: $$3y + 12 - 12 = -12x - 12$$ $$3y = -12x - 12$$ - Divide both sides by 3: $$\cancel{3}y = \frac{-12x - 12}{\cancel{3}}$$ $$y = -4x - 4$$ 4. **Solve equation 16: $x - 4y + 8 = 0$** - Subtract $x$ and 8 from both sides: $$x - 4y + 8 - x - 8 = 0 - x - 8$$ $$-4y = -x - 8$$ - Divide both sides by $-4$: $$\cancel{-4}y = \frac{-x - 8}{\cancel{-4}}$$ $$y = \frac{-x}{-4} + \frac{-8}{-4} = \frac{1}{4}x + 2$$ **Final answers:** - Equation 15 in slope-intercept form: $$y = -4x - 4$$ - Equation 16 in slope-intercept form: $$y = \frac{1}{4}x + 2$$