1. **State the problem:** Solve the first equation for the unknowns $m$ and $n$. Given: $$2(3 + m) = n$$ 2. **Isolate the first unknown $m$:** Start by expanding the left side: $$2 \times 3 + 2 \times m = n$$ $$6 + 2m = n$$ 3. **Express $m$ in terms of $n$:** Subtract 6 from both sides: $$6 + 2m - 6 = n - 6$$ $$2m = n - 6$$ Divide both sides by 2: $$\cancel{2}m = \frac{n - 6}{\cancel{2}}$$ $$m = \frac{n - 6}{2}$$ 4. **Express $n$ in terms of $m$:** From the original equation: $$n = 2(3 + m)$$ $$n = 6 + 2m$$ 5. **Summary:** - $m$ in terms of $n$ is $$m = \frac{n - 6}{2}$$ - $n$ in terms of $m$ is $$n = 6 + 2m$$ This completes the solution for the first problem.