1. The problem is to solve the equation $3k = 1$ for $k$. 2. The formula used here is to isolate the variable by dividing both sides of the equation by the coefficient of $k$. 3. Divide both sides by 3: $$k = \frac{1}{3}$$ 4. To show the cancellation explicitly: $$k = \frac{\cancel{3} \times k}{\cancel{3}} = \frac{1}{3}$$ 5. Therefore, the solution is $k = \frac{1}{3}$. This means that when $k$ is one third, the equation $3k = 1$ holds true.