1. **State the problem:** Solve for $x$ in the equation $$x = \frac{-9}{-9}$$ and verify the value of $x$. 2. **Recall the rule:** Dividing two negative numbers results in a positive number. 3. **Calculate:** $$x = \frac{-9}{-9} = 1$$ 4. **Check the user's claim:** The user states $x = -3$, but from the calculation, $x = 1$. 5. **Conclusion:** The correct value of $x$ is $1$, not $-3$. 1. **State the problem:** Solve the system of equations: $$x = 1 - 3y$$ $$3x + 3y = 15$$ 2. **Substitute $x$ from the first equation into the second:** $$3(1 - 3y) + 3y = 15$$ 3. **Expand and simplify:** $$3 - 9y + 3y = 15$$ $$3 - 6y = 15$$ 4. **Isolate $y$:** $$-6y = 15 - 3$$ $$-6y = 12$$ 5. **Divide both sides by $-6$:** $$y = \frac{12}{\cancel{-6}} \times \frac{\cancel{-1}}{\cancel{-1}} = -2$$ 6. **Substitute $y = -2$ back into $x = 1 - 3y$:** $$x = 1 - 3(-2) = 1 + 6 = 7$$ 7. **Final solution:** $$x = 7, \quad y = -2$$