1. **State the problem:** We need to solve the equation $$30 = \frac{5}{9}(F - 32)$$ for the temperature $F$ in degrees Fahrenheit. 2. **Recall the formula:** The equation relates Celsius ($C$) and Fahrenheit ($F$) temperatures by $$C = \frac{5}{9}(F - 32)$$. 3. **Substitute the given Celsius value:** Here, $C = 30$, so the equation is $$30 = \frac{5}{9}(F - 32)$$. 4. **Isolate $F - 32$ by multiplying both sides by 9:** $$9 \times 30 = 9 \times \frac{5}{9}(F - 32)$$ $$270 = \cancel{9} \times \frac{5}{\cancel{9}}(F - 32)$$ $$270 = 5(F - 32)$$ 5. **Divide both sides by 5 to isolate $(F - 32)$:** $$\frac{270}{5} = \frac{5(F - 32)}{5}$$ $$\frac{\cancel{270}}{\cancel{5}} = F - 32$$ $$54 = F - 32$$ 6. **Add 32 to both sides to solve for $F$:** $$54 + 32 = F - 32 + 32$$ $$86 = F$$ **Final answer:** The temperature in Fahrenheit is $$\boxed{86}$$ degrees.