1. **State the problem:** Solve for $a$ in the equation $2a + 0.8\overline{3} = 4.6\overline{6}$.
2. **Understand repeating decimals:**
- $0.8\overline{3}$ means $0.8333\ldots$
- $4.6\overline{6}$ means $4.6666\ldots$
3. **Convert repeating decimals to fractions:**
- Let $x = 0.8\overline{3}$.
Multiply by 10: $10x = 8.3\overline{3}$.
Subtract original: $10x - x = 8.3\overline{3} - 0.8\overline{3} \Rightarrow 9x = 7.5$.
So, $x = \frac{7.5}{9} = \frac{15}{18} = \frac{5}{6}$.
- Let $y = 4.6\overline{6}$.
Multiply by 10: $10y = 46.6\overline{6}$.
Subtract original: $10y - y = 46.6\overline{6} - 4.6\overline{6} \Rightarrow 9y = 42$.
So, $y = \frac{42}{9} = \frac{14}{3}$.
4. **Rewrite the equation with fractions:**
$$2a + \frac{5}{6} = \frac{14}{3}$$
5. **Isolate $a$:**
$$2a = \frac{14}{3} - \frac{5}{6}$$
6. **Find common denominator and subtract:**
$$\frac{14}{3} = \frac{28}{6}$$
$$2a = \frac{28}{6} - \frac{5}{6} = \frac{23}{6}$$
7. **Divide both sides by 2:**
$$a = \frac{\frac{23}{6}}{2} = \frac{23}{6} \times \frac{1}{2} = \frac{23}{12}$$
8. **Final answer:**
$$a = \frac{23}{12}$$ or approximately $1.9167$.
This means $a$ is $\frac{23}{12}$ which is a little less than 2.
Solve For A 8A612C
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