1. **State the problem:** Solve for $b$ in the equation $16 = \frac{5}{3}(40) + b$. 2. **Write the formula and explain:** We want to isolate $b$ on one side. The equation is of the form $16 = \frac{5}{3} \times 40 + b$. 3. **Calculate the multiplication:** $$\frac{5}{3} \times 40 = \frac{5 \times 40}{3} = \frac{200}{3}$$ 4. **Rewrite the equation:** $$16 = \frac{200}{3} + b$$ 5. **Isolate $b$ by subtracting $\frac{200}{3}$ from both sides:** $$b = 16 - \frac{200}{3}$$ 6. **Convert 16 to a fraction with denominator 3:** $$16 = \frac{48}{3}$$ 7. **Subtract the fractions:** $$b = \frac{48}{3} - \frac{200}{3} = \frac{48 - 200}{3} = \frac{-152}{3}$$ 8. **Final answer:** $$b = -\frac{152}{3}$$ This means $b$ is $-\frac{152}{3}$ or approximately $-50.67$.