1. **State the problem:** Solve for $c$ in the equation $Bc - 3c = 15$. 2. **Identify the formula and rules:** We can factor out $c$ from the left side since it is common in both terms. 3. **Factor the left side:** $$Bc - 3c = c(B - 3)$$ 4. **Rewrite the equation:** $$c(B - 3) = 15$$ 5. **Solve for $c$ by dividing both sides by $(B - 3)$:** $$c = \frac{15}{B - 3}$$ 6. **Show cancellation step:** $$c = \frac{\cancel{15}}{\cancel{B - 3}}$$ (This step shows division by the factor $B - 3$, assuming $B \neq 3$ to avoid division by zero.) 7. **Final answer:** $$c = \frac{15}{B - 3}$$ This means $c$ is equal to 15 divided by the quantity $B - 3$. Make sure $B \neq 3$ to keep the expression valid.