Subjects algebra

Solve For N 9Df907

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1. **State the problem:** Solve for $n$ in the equation $$24=3(n-5)$$. 2. **Use the distributive property:** Multiply 3 by each term inside the parentheses: $$24=3n-15$$ 3. **Isolate the term with $n$:** Add 15 to both sides to move the constant term: $$24+15=3n-15+15$$ $$39=3n$$ 4. **Divide both sides by 3 to solve for $n$:** $$\frac{39}{\cancel{3}}=\frac{3n}{\cancel{3}}$$ $$13=n$$ 5. **Final answer:** $$n=13$$