Subjects algebra

Solve For P 436B1B

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1. **State the problem:** Solve the equation $$D 4 - (3p) - 2 = p - 10$$ for $p$. 2. **Rewrite the equation clearly:** $$4 - 3p - 2 = p - 10$$ 3. **Simplify the left side:** $$4 - 2 = 2$$ so the equation becomes $$2 - 3p = p - 10$$ 4. **Add $3p$ to both sides to get all $p$ terms on one side:** $$2 - \cancel{3p} + 3p = p + 3p - 10$$ $$2 = 4p - 10$$ 5. **Add 10 to both sides to isolate the term with $p$:** $$2 + 10 = 4p - 10 + 10$$ $$12 = 4p$$ 6. **Divide both sides by 4 to solve for $p$:** $$\frac{12}{\cancel{4}} = \frac{4p}{\cancel{4}}$$ $$3 = p$$ 7. **Final answer:** $$p = 3$$ This means the value of $p$ that satisfies the equation is 3.