1. **State the problem:** Find the value of $p$ such that the expressions $2(p + 5)$ and $3(2p - 1)$ are equal.
2. **Write the equation:**
$$2(p + 5) = 3(2p - 1)$$
3. **Apply the distributive property:**
$$2p + 10 = 6p - 3$$
4. **Bring all terms involving $p$ to one side and constants to the other:**
$$2p + 10 = 6p - 3$$
Subtract $2p$ from both sides:
$$\cancel{2p} + 10 = 6p - 3 - \cancel{2p}$$
$$10 = 4p - 3$$
5. **Add 3 to both sides to isolate the term with $p$:**
$$10 + 3 = 4p - 3 + 3$$
$$13 = 4p$$
6. **Divide both sides by 4 to solve for $p$:**
$$\frac{13}{\cancel{4}} = \frac{4p}{\cancel{4}}$$
$$p = \frac{13}{4}$$
**Final answer:**
$$p = \frac{13}{4}$$
Solve For P 7Cd10F
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.