1. **State the problem:** Oscar thinks of a number $r$. He squares it to get $r^2$, multiplies by 4 to get $4r^2$, divides by 3 to get $\frac{4r^2}{3}$, then adds 7 to get 55. We need to find $r$.
2. **Write the equation:**
$$\frac{4r^2}{3} + 7 = 55$$
3. **Isolate the term with $r^2$:**
Subtract 7 from both sides:
$$\frac{4r^2}{3} = 55 - 7$$
$$\frac{4r^2}{3} = 48$$
4. **Clear the denominator:**
Multiply both sides by 3:
$$4r^2 = 48 \times 3$$
$$4r^2 = 144$$
5. **Solve for $r^2$:**
Divide both sides by 4:
$$r^2 = \frac{144}{4}$$
$$r^2 = 36$$
6. **Find $r$:**
Take the square root of both sides:
$$r = \pm \sqrt{36}$$
$$r = \pm 6$$
**Final answer:** $r = 6$ or $r = -6$
Solve For R 86266A
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