1. **State the problem:** Solve the equation $$\frac{-98}{15} + 6.2 = t - 3$$ 2. **Rewrite the equation:** $$\frac{-98}{15} + 6.2 = t - 3$$ 3. **Convert 6.2 to a fraction for easier calculation:** $$6.2 = \frac{62}{10} = \frac{31}{5}$$ 4. **Find a common denominator to add $$\frac{-98}{15}$$ and $$\frac{31}{5}$$:** The common denominator is 15. 5. **Rewrite $$\frac{31}{5}$$ with denominator 15:** $$\frac{31}{5} = \frac{31 \times 3}{5 \times 3} = \frac{93}{15}$$ 6. **Add the fractions:** $$\frac{-98}{15} + \frac{93}{15} = \frac{-98 + 93}{15} = \frac{-5}{15}$$ 7. **Simplify the fraction:** $$\frac{-5}{15} = \frac{\cancel{-5}}{\cancel{15}} = \frac{-1}{3}$$ 8. **Rewrite the equation with simplified sum:** $$\frac{-1}{3} = t - 3$$ 9. **Add 3 to both sides to isolate $$t$$:** $$\frac{-1}{3} + 3 = t$$ 10. **Convert 3 to fraction with denominator 3:** $$3 = \frac{9}{3}$$ 11. **Add the fractions:** $$\frac{-1}{3} + \frac{9}{3} = \frac{-1 + 9}{3} = \frac{8}{3}$$ 12. **Final answer:** $$t = \frac{8}{3}$$