1. The problem is to understand the expression "on 12 it has x" which seems incomplete or unclear. 2. Since the problem is not fully stated, let's interpret it as solving for $x$ in an equation involving 12 and $x$. 3. For example, if the problem is $12 = x$, then the solution is simply $x = 12$. 4. If you meant an equation like $12x = 0$, then dividing both sides by 12 gives $$\cancel{12}x = \cancel{12}0 \implies x = 0$$. 5. Please provide a complete equation or problem statement for a precise solution.