1. **State the problem:** We need to find the value of $x$ in the equation $$68 + 3x + 25 + x = 141$$ which represents the total number of students. 2. **Combine like terms:** Add the constants and the $x$ terms separately. $$68 + 25 = 93$$ $$3x + x = 4x$$ So the equation becomes: $$93 + 4x = 141$$ 3. **Isolate the variable term:** Subtract 93 from both sides to get: $$4x = 141 - 93$$ 4. **Simplify the right side:** $$4x = 48$$ 5. **Solve for $x$:** Divide both sides by 4. $$x = \frac{48}{4}$$ 6. **Cancel common factors:** $$x = \cancel{\frac{48}{4}} = 12$$ **Final answer:** $$\boxed{12}$$