1. **State the problem:** Solve the equation $$\frac{48}{c-1} = 3$$ for $c$. 2. **Use the formula:** To solve for $c$, multiply both sides of the equation by the denominator $(c-1)$ to eliminate the fraction. 3. **Multiply both sides:** $$\frac{48}{c-1} \times (c-1) = 3 \times (c-1)$$ which simplifies to $$48 = 3(c-1)$$ 4. **Distribute the 3:** $$48 = 3c - 3$$ 5. **Add 3 to both sides:** $$48 + 3 = 3c - 3 + 3$$ $$51 = 3c$$ 6. **Divide both sides by 3:** $$\frac{51}{\cancel{3}} = \frac{3c}{\cancel{3}}$$ $$17 = c$$ 7. **Final answer:** $$c = 17$$ This means the value of $c$ that satisfies the equation is 17.