1. **State the problem:** Given the function $f(x) = 4\sqrt{x} + 3$, solve for $x$ when $f(x) = 10$.
2. **Set up the equation:**
$$4\sqrt{x} + 3 = 10$$
3. **Isolate the square root term:**
$$4\sqrt{x} = 10 - 3$$
$$4\sqrt{x} = 7$$
4. **Divide both sides by 4:**
$$\cancel{4}\sqrt{x} = \frac{7}{\cancel{4}}$$
$$\sqrt{x} = \frac{7}{4}$$
5. **Square both sides to eliminate the square root:**
$$\left(\sqrt{x}\right)^2 = \left(\frac{7}{4}\right)^2$$
$$x = \frac{49}{16}$$
6. **Final answer:**
$$x = \frac{49}{16}$$
This is the exact solution for $x$ when $f(x) = 10$.
Solve Fx Eq Dead31
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