1. The problem is to solve the inequality $$6x \geq 108$$ and find all possible values of $x$ that satisfy it. 2. The formula used here is to isolate $x$ by dividing both sides of the inequality by 6. Important rule: when dividing or multiplying an inequality by a positive number, the inequality direction remains the same. 3. Divide both sides by 6: $$6x \geq 108$$ $$\cancel{6}x \geq \frac{108}{\cancel{6}}$$ $$x \geq 18$$ 4. This means $x$ must be greater than or equal to 18 to satisfy the inequality. 5. Checking the options: - $x=6$ does not satisfy $x \geq 18$. - $x=17$ does not satisfy $x \geq 18$. - $x=18$ satisfies $x \geq 18$. - $x=25$ satisfies $x \geq 18$ but was not marked in the original selection. 6. Therefore, the correct solutions are $x=18$ and $x=25$. Final answer: $x \geq 18$ which includes $x=18$ and $x=25$.