1. **State the problem:** Solve the inequality $$8x + 3 \leq 43$$ and verify the solution $$x \leq 5$$.
2. **Write the inequality:** $$8x + 3 \leq 43$$
3. **Isolate the term with $$x$$:** Subtract 3 from both sides:
$$8x + 3 - 3 \leq 43 - 3$$
$$8x \leq 40$$
4. **Divide both sides by 8 to solve for $$x$$:**
$$\frac{8x}{\cancel{8}} \leq \frac{40}{\cancel{8}}$$
$$x \leq 5$$
5. **Interpretation:** The solution to the inequality is $$x \leq 5$$, which matches the handwritten solution.
**Final answer:** $$x \leq 5$$
Solve Inequality 307Ff7
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