Subjects algebra

Solve Inequality 307Ff7

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1. **State the problem:** Solve the inequality $$8x + 3 \leq 43$$ and verify the solution $$x \leq 5$$. 2. **Write the inequality:** $$8x + 3 \leq 43$$ 3. **Isolate the term with $$x$$:** Subtract 3 from both sides: $$8x + 3 - 3 \leq 43 - 3$$ $$8x \leq 40$$ 4. **Divide both sides by 8 to solve for $$x$$:** $$\frac{8x}{\cancel{8}} \leq \frac{40}{\cancel{8}}$$ $$x \leq 5$$ 5. **Interpretation:** The solution to the inequality is $$x \leq 5$$, which matches the handwritten solution. **Final answer:** $$x \leq 5$$