1. **State the problem:** We are given a function $f$ with vertical asymptotes at $x=-2$ and $x=2$, and a horizontal asymptote at $y=0$. We need to solve the inequality $f(x)<0$ using the graph. 2. **Analyze the graph:** The graph has three branches: - Left branch: below $y=0$ and to the left of $x=-2$. - Middle branch: passes through $(0,0)$, between $x=-2$ and $x=2$, crossing the $x$-axis at $0$. - Right branch: above $y=0$ and to the right of $x=2$. 3. **Identify where $f(x)<0$:** - Left branch is below $0$ for $x < -2$. - Middle branch is below $0$ between $-2 < x < 0$. - Right branch is above $0$ for $x > 2$. 4. **Write the solution in interval notation:** $$(-\infty, -2) \cup (-2, 0)$$ Note that $x=-2$ is a vertical asymptote (not included), and at $x=0$, $f(0)=0$ so $0$ is not included for $<$ inequality. **Final answer:** $$\boxed{(-\infty, -2) \cup (-2, 0)}$$