1. The problem is to solve the inequality $$-5 > \frac{y}{3}$$ for $y$. 2. To isolate $y$, we multiply both sides of the inequality by 3. Since 3 is positive, the inequality direction remains the same. 3. Multiplying both sides: $$3 \times (-5) > 3 \times \frac{y}{3}$$ 4. Simplify the right side by canceling 3: $$-15 > \cancel{3} \times \frac{y}{\cancel{3}}$$ 5. This simplifies to: $$-15 > y$$ 6. The solution is all $y$ such that $y < -15$ (rewriting the inequality in a more standard form). 7. In plain language: $y$ must be less than $-15$ to satisfy the inequality.