1. The problem is to solve the inequality $-4 > - \frac{4}{3} s$ for $s$. 2. To isolate $s$, first multiply both sides of the inequality by $-1$ to remove the negative signs. Remember, multiplying an inequality by a negative number reverses the inequality sign. 3. Multiplying both sides by $-1$: $$-4 > - \frac{4}{3} s \implies \cancel{-1} \times (-4) < \cancel{-1} \times \left(- \frac{4}{3} s\right)$$ $$4 < \frac{4}{3} s$$ 4. Now, to solve for $s$, multiply both sides by the reciprocal of $\frac{4}{3}$, which is $\frac{3}{4}$: $$4 < \frac{4}{3} s \implies 4 \times \frac{3}{4} < \frac{4}{3} s \times \frac{3}{4}$$ $$\cancel{4} \times \frac{3}{\cancel{4}} < s$$ $$3 < s$$ 5. The solution is $s > 3$. This means $s$ must be greater than 3 for the original inequality to hold true.