1. **State the problem:** Solve the inequality $5x + 3 > 2x - 7$.
2. **Isolate the variable terms:** Subtract $2x$ from both sides to get all $x$ terms on one side.
$$5x + 3 > 2x - 7$$
$$5x - \cancel{2x} + 3 > \cancel{2x} - 7$$
$$3x + 3 > -7$$
3. **Isolate the constant terms:** Subtract 3 from both sides.
$$3x + \cancel{3} > -7 - \cancel{3}$$
$$3x > -10$$
4. **Solve for $x$:** Divide both sides by 3.
$$\frac{3x}{\cancel{3}} > \frac{-10}{\cancel{3}}$$
$$x > -\frac{10}{3}$$
5. **Interpretation:** The solution to the inequality is all $x$ values greater than $-\frac{10}{3}$.
**Final answer:**
$$x > -\frac{10}{3}$$
Solve Inequality Ab50Bd
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