1. **State the problem:** Solve the inequality $$4 > -8x$$.
2. **Recall the rule for inequalities:** When dividing or multiplying both sides of an inequality by a negative number, the inequality sign must be reversed.
3. **Isolate $x$:** Divide both sides by $-8$ (a negative number), so we must reverse the inequality sign:
$$4 > -8x$$
Divide both sides by $\cancel{-8}$ with reversal:
$$\frac{4}{\cancel{-8}} < x$$
4. **Simplify the fraction:**
$$\frac{4}{-8} = -\frac{1}{2}$$
So,
$$x > -\frac{1}{2}$$
5. **Interpretation:** The solution is all $x$ values greater than $-\frac{1}{2}$.
**Final answer:** $$x > -\frac{1}{2}$$
Solve Inequality Fa016B
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