1. **State the problem:** Solve the linear equation $$\frac{1}{3}x + 4 = 2$$.
2. **Isolate the variable term:** Subtract 4 from both sides to get $$\frac{1}{3}x + 4 - 4 = 2 - 4$$ which simplifies to $$\frac{1}{3}x = -2$$.
3. **Eliminate the fraction:** Multiply both sides by 3 to solve for $$x$$:
$$3 \times \frac{1}{3}x = 3 \times (-2)$$
This gives $$\cancel{3} \times \frac{1}{\cancel{3}} x = -6$$, so $$x = -6$$.
4. **Check the solution:** Substitute $$x = -6$$ back into the original equation:
$$\frac{1}{3}(-6) + 4 = -2 + 4 = 2$$ which is true.
**Final answer:** $$x = -6$$.
Solve Linear 0Aca90
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