1. The problem is to solve for $x$ in the equation $2x + 3 = 11$. 2. The formula used here is to isolate $x$ by performing inverse operations. We subtract 3 from both sides to undo the addition, then divide both sides by 2 to undo the multiplication. 3. Subtract 3 from both sides: $$2x + 3 - 3 = 11 - 3$$ $$2x = 8$$ 4. Divide both sides by 2: $$\frac{\cancel{2}x}{\cancel{2}} = \frac{8}{2}$$ $$x = 4$$ 5. Therefore, the solution is $x = 4$. This means when $x$ is 4, the original equation holds true.