Subjects algebra

Solve Linear 4A89Ea

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1. **State the problem:** Solve the equation $5x - 3 = 2s + 6$ for $x$ in terms of $s$. 2. **Formula and rules:** To isolate $x$, we need to get all terms involving $x$ on one side and constants on the other. We can add or subtract terms on both sides and divide both sides by coefficients. 3. **Isolate $x$:** $$5x - 3 = 2s + 6$$ Add 3 to both sides: $$5x - 3 + 3 = 2s + 6 + 3$$ $$5x = 2s + 9$$ 4. **Divide both sides by 5 to solve for $x$:** $$x = \frac{2s + 9}{5}$$ Show cancellation explicitly: $$x = \frac{\cancel{5} \cdot \frac{2s + 9}{\cancel{5}}}{1} = \frac{2s + 9}{5}$$ 5. **Final answer:** $$x = \frac{2s + 9}{5}$$ This means $x$ depends on $s$ and is equal to the fraction of $2s + 9$ over 5.