1. **State the problem:** We need to find the value of $x$ such that $f(x) = 4$ where $f(x) = 2x + 2$. 2. **Write the equation:** Set $f(x)$ equal to 4: $$2x + 2 = 4$$ 3. **Isolate $x$:** Subtract 2 from both sides: $$2x + \cancel{2} - \cancel{2} = 4 - 2$$ $$2x = 2$$ 4. **Solve for $x$:** Divide both sides by 2: $$\frac{2x}{\cancel{2}} = \frac{2}{\cancel{2}}$$ $$x = 1$$ 5. **Conclusion:** The value of $x$ that satisfies $f(x) = 4$ is $x = 1$. Note: The graph described is of $y = x^2 - 1$, which is unrelated to the linear function $f(x) = 2x + 2$ in this problem.