1. **State the problem:** Solve the equation $6y + 11 = 3y + 5$ for $y$. 2. **Isolate the variable terms:** Subtract $3y$ from both sides to get all $y$ terms on one side. $$6y + 11 - \cancel{3y} = 3y + 5 - \cancel{3y}$$ $$3y + 11 = 5$$ 3. **Isolate the constant terms:** Subtract 11 from both sides to move constants to the other side. $$3y + 11 - \cancel{11} = 5 - \cancel{11}$$ $$3y = -6$$ 4. **Solve for $y$:** Divide both sides by 3 to isolate $y$. $$\frac{3y}{\cancel{3}} = \frac{-6}{\cancel{3}}$$ $$y = -2$$ 5. **Final answer:** The solution to the equation is $y = -2$.