1. **State the problem:** Solve the linear equation $2x + 3y = 9$ for $y$ in terms of $x$. 2. **Formula and rules:** To solve for $y$, isolate $y$ on one side of the equation by moving other terms to the opposite side and then dividing by the coefficient of $y$. 3. **Isolate $y$:** $$2x + 3y = 9$$ Subtract $2x$ from both sides: $$3y = 9 - 2x$$ 4. **Divide both sides by 3:** $$y = \frac{9 - 2x}{3}$$ Show cancellation: $$y = \frac{\cancel{3} \times 3 - 2x}{\cancel{3} \times 1} = 3 - \frac{2}{3}x$$ 5. **Final expression:** $$y = 3 - \frac{2}{3}x$$ This expresses $y$ in terms of $x$ and is the solution to the equation.