Subjects algebra

Solve Linear 96C1B4

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1. **State the problem:** Solve the equation $$\frac{2x+4}{3} = 5$$ for $x$. 2. **Formula and rules:** To solve for $x$, multiply both sides of the equation by the denominator to eliminate the fraction. Then isolate $x$ by performing inverse operations. 3. **Multiply both sides by 3:** $$\cancel{3} \times \frac{2x+4}{\cancel{3}} = 5 \times 3$$ which simplifies to $$2x + 4 = 15$$ 4. **Subtract 4 from both sides:** $$2x + 4 - 4 = 15 - 4$$ $$2x = 11$$ 5. **Divide both sides by 2:** $$\frac{2x}{\cancel{2}} = \frac{11}{\cancel{2}}$$ $$x = \frac{11}{2}$$ 6. **Final answer:** $$x = \frac{11}{2}$$ or 5.5. This means the value of $x$ that satisfies the equation is $\frac{11}{2}$.