Subjects algebra

Solve Linear 9864B6

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1. The problem is to find the value of $x$ in the equation $$\frac{2x+3}{4} = 5.$$ 2. The formula used here is to solve linear equations by isolating the variable $x$. 3. Multiply both sides of the equation by 4 to eliminate the denominator: $$4 \times \frac{2x+3}{4} = 4 \times 5$$ 4. This simplifies to: $$\cancel{4} \times \frac{2x+3}{\cancel{4}} = 20$$ $$2x + 3 = 20$$ 5. Subtract 3 from both sides to isolate the term with $x$: $$2x + 3 - 3 = 20 - 3$$ $$2x = 17$$ 6. Divide both sides by 2 to solve for $x$: $$\frac{2x}{2} = \frac{17}{2}$$ $$\cancel{2}x/\cancel{2} = \frac{17}{2}$$ $$x = \frac{17}{2}$$ 7. The final answer is: $$x = \frac{17}{2} = 8.5$$