Subjects algebra

Solve Linear A407Da

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1. Solve the equation $2x + 3 = 11$. 2. Start by isolating $x$ on one side. 3. Subtract 3 from both sides: $$2x + 3 - 3 = 11 - 3$$ $$2x = 8$$ 4. Divide both sides by 2: $$\frac{\cancel{2}x}{\cancel{2}} = \frac{8}{2}$$ $$x = 4$$ 5. The solution is $x = 4$. This means when $x$ is 4, the equation $2x + 3 = 11$ holds true.