1. Stating the problem: We need to find the value of $x$ such that $f(x) = 19$ for the function $f(x) = 2x + 3$.
2. Write the equation:
$$2x + 3 = 19$$
3. Subtract 3 from both sides to isolate the term with $x$:
$$2x + \cancel{3} - \cancel{3} = 19 - 3$$
$$2x = 16$$
4. Divide both sides by 2 to solve for $x$:
$$\frac{2x}{\cancel{2}} = \frac{16}{\cancel{2}}$$
$$x = 8$$
5. Final answer: The value of $x$ for which $f(x) = 19$ is $x = 8$.
Solve Linear B94B02
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