1. **State the problem:** Solve the equation $$6 = 18 + \frac{h}{3}$$ for the variable $h$. 2. **Isolate the term with $h$:** To solve for $h$, first subtract 18 from both sides: $$6 - 18 = 18 + \frac{h}{3} - 18$$ which simplifies to $$-12 = \frac{h}{3}$$ 3. **Solve for $h$:** Multiply both sides by 3 to cancel the denominator: $$3 \times (-12) = 3 \times \frac{h}{3}$$ which gives $$-36 = \cancel{3} \times \frac{h}{\cancel{3}} = h$$ 4. **Final answer:** $$h = -36$$ This means the value of $h$ that satisfies the equation is $-36$.