1. **State the problem:** Solve the equation $4(x+1)=2x+4$ for $x$.
2. **Write down the equation:**
$$4(x+1)=2x+4$$
3. **Distribute the 4 on the left side:**
$$4 \times x + 4 \times 1 = 2x + 4$$
$$4x + 4 = 2x + 4$$
4. **Subtract $2x$ from both sides to get all $x$ terms on one side:**
$$4x + 4 - 2x = 2x + 4 - 2x$$
$$\cancel{4x} + 4 - \cancel{2x} = \cancel{2x} + 4 - \cancel{2x}$$
$$2x + 4 = 4$$
5. **Subtract 4 from both sides to isolate the $x$ term:**
$$2x + 4 - 4 = 4 - 4$$
$$2x + \cancel{4} - \cancel{4} = \cancel{4} - \cancel{4}$$
$$2x = 0$$
6. **Divide both sides by 2 to solve for $x$:**
$$\frac{2x}{2} = \frac{0}{2}$$
$$\cancel{2}x / \cancel{2} = 0$$
$$x = 0$$
**Final answer:**
$$x = 0$$
Solve Linear Ca2Efe
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