1. We start with the problem: Solve the equation $$\frac{1}{2}x - 5 = \frac{3}{4}x + 2$$.
2. The goal is to isolate $x$ on one side. First, subtract $\frac{3}{4}x$ from both sides:
$$\frac{1}{2}x - \frac{3}{4}x - 5 = 2$$
3. Simplify the left side by finding a common denominator for the $x$ terms:
$$\frac{2}{4}x - \frac{3}{4}x - 5 = 2$$
4. Combine like terms:
$$\left(\frac{2}{4} - \frac{3}{4}\right)x - 5 = 2$$
$$-\frac{1}{4}x - 5 = 2$$
5. Add 5 to both sides to isolate the term with $x$:
$$-\frac{1}{4}x = 2 + 5$$
$$-\frac{1}{4}x = 7$$
6. Multiply both sides by $-4$ to solve for $x$:
$$\cancel{-\frac{1}{4}}x \times \cancel{-4} = 7 \times (-4)$$
$$x = -28$$
Final answer: $$x = -28$$
Solve Linear Cb06Ad
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