Subjects algebra

Solve Linear Equation 0D4899

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1. **State the problem:** Solve the equation $\frac{5y - 15}{5} = 3$ for $y$. 2. **Formula and rules:** To solve for $y$, we need to isolate $y$ on one side of the equation. We can do this by eliminating the denominator and then simplifying. 3. **Eliminate the denominator:** Multiply both sides of the equation by 5 to cancel the denominator: $$\cancel{5} \times \frac{5y - 15}{\cancel{5}} = 3 \times 5$$ which simplifies to $$5y - 15 = 15$$ 4. **Isolate $y$:** Add 15 to both sides: $$5y - 15 + 15 = 15 + 15$$ $$5y = 30$$ 5. **Solve for $y$:** Divide both sides by 5: $$\frac{\cancel{5}y}{\cancel{5}} = \frac{30}{5}$$ $$y = 6$$ **Final answer:** $y = 6$