1. The problem is to find the value of $x$ in the equation $$\frac{2x+3}{4} = 5.$$ 2. The formula used here is to solve for $x$ by isolating it on one side of the equation. We do this by multiplying both sides by the denominator to cancel the fraction. 3. Multiply both sides by 4: $$4 \times \frac{2x+3}{4} = 4 \times 5$$ This simplifies to: $$\cancel{4} \times \frac{2x+3}{\cancel{4}} = 20$$ 4. Now the equation is: $$2x + 3 = 20$$ 5. Subtract 3 from both sides to isolate the term with $x$: $$2x + 3 - 3 = 20 - 3$$ $$2x = 17$$ 6. Divide both sides by 2 to solve for $x$: $$\frac{2x}{2} = \frac{17}{2}$$ $$\cancel{2}x/\cancel{2} = \frac{17}{2}$$ $$x = \frac{17}{2}$$ 7. The final answer is: $$x = \frac{17}{2} = 8.5$$