Subjects algebra

Solve Linear Equation 38D73B

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1. **State the problem:** Solve the equation $$20 - \frac{t}{3} = 14$$ for $t$. 2. **Isolate the term with $t$:** Subtract 20 from both sides: $$20 - \frac{t}{3} - 20 = 14 - 20$$ which simplifies to $$- \frac{t}{3} = -6$$ 3. **Remove the negative sign:** Multiply both sides by $-1$: $$\cancel{-1} \times - \frac{t}{3} = \cancel{-1} \times -6$$ which gives $$\frac{t}{3} = 6$$ 4. **Solve for $t$:** Multiply both sides by 3 to cancel the denominator: $$3 \times \frac{t}{3} = 3 \times 6$$ which simplifies to $$\cancel{3} \times \frac{t}{\cancel{3}} = 18$$ so $$t = 18$$ **Final answer:** $$t = 18$$