1. **State the problem:** Solve the equation $$20 - \frac{t}{3} = 14$$ for $t$.
2. **Isolate the term with $t$:** Subtract 20 from both sides:
$$20 - \frac{t}{3} - 20 = 14 - 20$$
which simplifies to
$$- \frac{t}{3} = -6$$
3. **Remove the negative sign:** Multiply both sides by $-1$:
$$\cancel{-1} \times - \frac{t}{3} = \cancel{-1} \times -6$$
which gives
$$\frac{t}{3} = 6$$
4. **Solve for $t$:** Multiply both sides by 3 to cancel the denominator:
$$3 \times \frac{t}{3} = 3 \times 6$$
which simplifies to
$$\cancel{3} \times \frac{t}{\cancel{3}} = 18$$
so
$$t = 18$$
**Final answer:** $$t = 18$$
Solve Linear Equation 38D73B
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