1. **State the problem:** Solve the equation $$8 - 50 - c = 5c - 2$$ for $c$. 2. **Simplify both sides:** Combine like terms on the left side: $$8 - 50 - c = -42 - c$$ So the equation becomes: $$-42 - c = 5c - 2$$ 3. **Isolate variable terms:** Add $c$ to both sides to move all $c$ terms to the right: $$-42 - \cancel{c} + c = 5c - 2 + c$$ which simplifies to: $$-42 = 6c - 2$$ 4. **Isolate the constant term on the left:** Add 2 to both sides: $$-42 + 2 = 6c - 2 + 2$$ which simplifies to: $$-40 = 6c$$ 5. **Solve for $c$ by dividing both sides by 6:** $$\frac{-40}{6} = \frac{6c}{6}$$ Show cancellation: $$\frac{-40}{\cancel{6}} = \cancel{6}c / \cancel{6}$$ Simplify the fraction: $$c = -\frac{20}{3}$$ **Final answer:** $$c = -\frac{20}{3}$$