Subjects algebra

Solve Linear Equation 4Ebbd8

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1. **State the problem:** Solve the equation $6q + 3q - q = 24$ for $q$. 2. **Combine like terms:** Add the coefficients of $q$ on the left side. $$6q + 3q - q = (6 + 3 - 1)q = 8q$$ So the equation becomes: $$8q = 24$$ 3. **Isolate $q$:** Divide both sides by 8 to solve for $q$. $$\frac{\cancel{8}q}{\cancel{8}} = \frac{24}{8}$$ $$q = 3$$ 4. **Final answer:** The value of $q$ is 3.