Subjects algebra

Solve Linear Equation 54Caa8

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1. **State the problem:** We are given the equation $a = 3(2m - 4)$ and values for $a$ and $m$ in one year: $a = 19$ and $m = 6$. We want to check if these values satisfy the equation and solve for $a$ when $m=6$. 2. **Substitute the given value of $m$ into the equation:** $$a = 3(2 \times 6 - 4)$$ 3. **Simplify inside the parentheses:** $$a = 3(12 - 4)$$ 4. **Calculate the subtraction:** $$a = 3 \times 8$$ 5. **Multiply:** $$a = 24$$ 6. **Compare with given $a=19$:** The equation gives $a=24$ when $m=6$, but the problem states $a=19$. Therefore, the values $a=19$ and $m=6$ do not satisfy the equation. **Final answer:** $$a = 24 \text{ when } m = 6$$ The given values do not satisfy the equation.