Subjects algebra

Solve Linear Equation 61Eae4

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1. **State the problem:** Solve the equation $$\frac{2x+4}{3} = 5$$ for $x$. 2. **Formula and rules:** To solve for $x$, multiply both sides of the equation by the denominator to eliminate the fraction. 3. Multiply both sides by 3: $$3 \times \frac{2x+4}{3} = 3 \times 5$$ This simplifies to: $$\cancel{3} \times \frac{2x+4}{\cancel{3}} = 15$$ which is: $$2x + 4 = 15$$ 4. Subtract 4 from both sides to isolate the term with $x$: $$2x + 4 - 4 = 15 - 4$$ $$2x = 11$$ 5. Divide both sides by 2 to solve for $x$: $$\frac{2x}{2} = \frac{11}{2}$$ $$\cancel{2}x / \cancel{2} = \frac{11}{2}$$ $$x = \frac{11}{2}$$ **Final answer:** $$x = \frac{11}{2}$$