1. **State the problem:** Solve the equation $$\frac{5x}{2} = 11 + \frac{2x}{3}$$ for $x$.
2. **Identify the goal:** We want to isolate $x$ on one side of the equation.
3. **Eliminate fractions:** Multiply both sides by the least common denominator (LCD) of 2 and 3, which is 6, to clear the denominators.
$$6 \times \frac{5x}{2} = 6 \times \left(11 + \frac{2x}{3}\right)$$
4. **Simplify each term:**
$$6 \times \frac{5x}{2} = \cancel{6} \times \frac{5x}{\cancel{2}} \times 3 = 15x$$
$$6 \times 11 = 66$$
$$6 \times \frac{2x}{3} = \cancel{6} \times \frac{2x}{\cancel{3}} \times 2 = 4x$$
So the equation becomes:
$$15x = 66 + 4x$$
5. **Isolate $x$ terms:** Subtract $4x$ from both sides:
$$15x - 4x = 66 + 4x - 4x$$
$$\cancel{15x} - \cancel{4x} = 66 + \cancel{4x} - \cancel{4x}$$
$$11x = 66$$
6. **Solve for $x$:** Divide both sides by 11:
$$\frac{11x}{11} = \frac{66}{11}$$
$$\cancel{11}x = 6$$
$$x = 6$$
**Final answer:** $x = 6$
Solve Linear Equation 6C2Bd2
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.