1. **State the problem:** Solve the equation $5(K+4) = 2(5K-3) + 12$ for $K$.
2. **Write the formula and rules:** Use the distributive property to expand both sides and then isolate the variable $K$.
3. **Expand both sides:**
$$5(K+4) = 5K + 20$$
$$2(5K-3) + 12 = 10K - 6 + 12 = 10K + 6$$
4. **Rewrite the equation:**
$$5K + 20 = 10K + 6$$
5. **Bring all terms involving $K$ to one side and constants to the other:**
$$5K + 20 = 10K + 6$$
$$5K - 10K = 6 - 20$$
$$\cancel{5K} - 10K = 6 - 20$$
$$-5K = -14$$
6. **Divide both sides by $-5$ to solve for $K$:**
$$K = \frac{-14}{-5}$$
$$K = \cancel{\frac{-14}{-5}} = \frac{14}{5}$$
7. **Final answer:**
$$K = \frac{14}{5}$$
Solve Linear Equation 70C10D
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