Subjects algebra

Solve Linear Equation 7Bdb8B

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Question: User: $-2r=16$
1. **State the problem:** Solve the equation $-2r=16$ for $r$. 2. **Formula and rules:** To solve for $r$, divide both sides of the equation by the coefficient of $r$, which is $-2$. 3. **Intermediate work:** $$-2r=16$$ Divide both sides by $-2$: $$\frac{-2r}{\cancel{-2}}=\frac{16}{\cancel{-2}}$$ 4. **Simplify:** $$r=-8$$ 5. **Explanation:** Dividing both sides by $-2$ isolates $r$ on the left side. The division cancels the $-2$ coefficient, leaving $r$ alone. On the right side, $16$ divided by $-2$ equals $-8$. Thus, the solution is $r=-8$.