Subjects algebra

Solve Linear Equation 8Bb0A4

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1. **State the problem:** Solve the equation $24y + 1 - 3 = 0$ for $y$. 2. **Simplify the equation:** Combine like terms on the left side. $$24y + 1 - 3 = 24y - 2$$ So the equation becomes: $$24y - 2 = 0$$ 3. **Isolate the variable term:** Add 2 to both sides. $$24y - 2 + 2 = 0 + 2$$ $$24y = 2$$ 4. **Solve for $y$:** Divide both sides by 24. $$\frac{\cancel{24}y}{\cancel{24}} = \frac{2}{24}$$ $$y = \frac{2}{24}$$ 5. **Simplify the fraction:** $$y = \frac{1}{12}$$ **Final answer:** $$y = \frac{1}{12}$$